Asked by alphonso deverny

The area of a particular parallelogram is given by the formula A=x^2−bx+c.

How can you rearrange this formula to correctly find the x-value that will yield the maximum area?

Answers

Answered by Reiny
first of all, x^2 - bx + c is a parabola opening upwards, so it doesn't have a
maximum, it has a minimum

dA/dx = 2x - b
= 0 for a min of A
2x - b= 0
2x= b
x = b/2
Answered by Anonymous
A=(x−b/2)^2+4c−b/4
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