Asked by C. Fenwick

Suppose that the antenna lengths of woodlice are approximately normally distributed with a mean of 0.2 inches and a standard deviation of 0.05 inches. What proportion of woodlice have antenna lengths that are more than 0.23 inches? Round your answer to at least four decimal places.
Answered by PsyDAG
Z = (score-mean)/SD

Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion/probability related to the Z score.
Answered by Bo
.7257
Answered by Anonymous
The distribution of heights of American women aged to is approximately normally distributed with a mean of inches and a standard deviation of inches. Calculate the -score for a woman six feet tall.
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