Asked by tanzil

the boys of a school can be arranged in 12, 15, 18 equal rows and also into a solid square. what is the least number of boys that the school can have? (hint: find the lcm) anwer is 900 explain
Answered by Steve
the number has to be evenly divisible by 12,15,18.

12 = 2^2 * 3
15 = 3 * 5
18 = 2 * 3^2
LCM is thus 2^2 * 3^2 * 5 = 180

But, we want the number to be a perfect square. Since it already is a multiple of 2^2 and 3^2, we just need to add a factor of 5 to get 5^2.

180*5 = 900
Answered by faisal
i can't understand this method. how we can create 5?
Answered by zaib
Hello
Dear a the quedtion solved .when we ake LCM 2 comes two time and 3 also omes two time and these two digits have there perfect square so we make the perfect square of 5 and we have to b multiply with 5 again so it become perfect multiply and the answer become 900 .
2^2*3^3*5=180*5=900
Answered by Naqash
Great job ....you are first...
Answered by Zuhaib King
The students in a school can be arranged in 12,15 and 18 equal rows and also into a solid square. What is the lowest number of students that can be in the school? (Hint:Find the LCM)
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