Asked by Kp
a rock is thrown straight up in the air from an initial height of ho, in metres, with the initial velocity vo, in metres per second. The height in metres above the ground after t seconds is given by h(t) = -4.9t^2 + vo + ho. Find an expression for the time it takes the rock to reach its maximum height.
Answers
Answered by
Steve
this just a parabola, with vertex at
t = -2vo/-9.8
t = -2vo/-9.8
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