Asked by Jay
A rock is thrown straight up at a velocity of +30. m/s from a height of 2 m above the ground. How high does it go? How long will it take to fall back to the same height from which it was thrown?
Answers
Answered by
oobleck
h(t) = 2 + 20t - 4.9t^2
as with all parabolas, the vertex is at t = -b/2a = 20/9.8
time down = time up
as with all parabolas, the vertex is at t = -b/2a = 20/9.8
time down = time up
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