Question
If I had a math problem 2x^4 x y^-4 x z^-3 / 3x^2 x y^-3 x z^4.
In simpler terms it would look like this:
2x^4 X y^-4 X z^-3
-------------------
3x^2 X y^-3 X z^4
When I tried to solve this I got 6x^2 X y^-1 X 2^-7. Am I correct? If not could you please help me on how to solve it.
In simpler terms it would look like this:
2x^4 X y^-4 X z^-3
-------------------
3x^2 X y^-3 X z^4
When I tried to solve this I got 6x^2 X y^-1 X 2^-7. Am I correct? If not could you please help me on how to solve it.
Answers
Steve
Nope. The coefficients just divide normally: 2/3
x^4/x^2 = x^2
y^-4/y^-3 = y^-1
z^-3/z^4 = z^-7
so, you wind up with
2/3 x^2 y^-1 z^-7, or
2x^2
--------
3yz^7
x^4/x^2 = x^2
y^-4/y^-3 = y^-1
z^-3/z^4 = z^-7
so, you wind up with
2/3 x^2 y^-1 z^-7, or
2x^2
--------
3yz^7