Asked by Ngau
Two rifles are fired at targets, which are 100 m away. The first rifle fires bullets at 1200 ft/s and the second fires a bullet at 3000 ft/s. How long will it take each bullet to get to the target? If both are aimed directly at the bull's-eye, how far will each bullet travel below the bull's-eye?
Answers
Answered by
MathMate
let α be the angle of the projectile with the horizontal as it leaves the muzzle.
Here α=0 degree.
Let vi=initial muzzle velocity, then
horizontal velocity, vh=vi*cos(α).
Time taken to reach the target
t=Horizontal distance/vh
where horizontal distance = 100m
Since acceleration due to gravity acts on the bullet during this time, then
vertical displacement
Dv=vi*sin(α)t-(1/2)gt²
where Dv is negative downwards.
Use consistent units in the above equations, for example metres and seconds.
Here α=0 degree.
Let vi=initial muzzle velocity, then
horizontal velocity, vh=vi*cos(α).
Time taken to reach the target
t=Horizontal distance/vh
where horizontal distance = 100m
Since acceleration due to gravity acts on the bullet during this time, then
vertical displacement
Dv=vi*sin(α)t-(1/2)gt²
where Dv is negative downwards.
Use consistent units in the above equations, for example metres and seconds.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.