Asked by KT

if possible, solve the nonlinear system of equations.
x^2+y^2=58
y-x=4

Answers

Answered by Reiny
from the 2nd ---> y = x+4
sub into the 1st

x^2 + (x+4)^2 = 58
2x^2 + 8x+16-58 = 0
x^2 + 4x - 21 = 0
(x+7)(x-3) = 0
x = -7 or x = 3

if x = -7, y = -7+4 = -3
if x = 3 , y = 3+4 = 7

x=3, y=7
or
x=-7, y = -3
Answered by KT
thank you x)
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