Asked by Mara *** Please, help me*
Wastewater from a small town is treated in a trickling filter which is preceeded by a screen, sand-removal and primary clarification. The maximum hydraulic capacity, or peak flow, of the treatment plant is
1,500 m3/h. The dry weather flow (Qdwf) amounts 7,500 m3/day, with a BOD concentration of 300 mg/l.
a) Calculate the so-called peak flow factor.
b) The cross-sectional surface area of the screen channel during maximum flow = 0.75 m2. The maximum free surface area in the clean screen = 0.5 m2. Use hL=1C⋅(V2−v2)(2⋅g) for calculating the head loss, the friction coefficient (C) for a clean screen is 0.7.
First, calculate the v in m/s.
Second, calculate the V in m/s.
c) Calculate the head loss in m.
1,500 m3/h. The dry weather flow (Qdwf) amounts 7,500 m3/day, with a BOD concentration of 300 mg/l.
a) Calculate the so-called peak flow factor.
b) The cross-sectional surface area of the screen channel during maximum flow = 0.75 m2. The maximum free surface area in the clean screen = 0.5 m2. Use hL=1C⋅(V2−v2)(2⋅g) for calculating the head loss, the friction coefficient (C) for a clean screen is 0.7.
First, calculate the v in m/s.
Second, calculate the V in m/s.
c) Calculate the head loss in m.
Answers
Answered by
Anonymous
Please, help me with this question... Thanks!
Answered by
Mara *** Please, help me*
Please, help me with this question... Thanks!
Answered by
bilal
V = 33
v = 20
HL = 0.97
v = 20
HL = 0.97
Answered by
Mara *** Please, help me*
Incorrect, all 3 of them :(
Answered by
Anonymous
Please, please, help!
Answered by
ham
mara i post some answer if you still around..
Answered by
Ham
Wastewater from a small town is treated in a trickling filter which is preceeded by a screen, sand-removal and primary clarification. The maximum hydraulic capacity, or peak flow, of the treatment plant is
1,500 m3/h. The dry weather flow (Qdwf) amounts 7,500 m3/day, with a BOD concentration of 300 mg/l.
a) Calculate the so-called peak flow factor. Answer=4.8
b) The cross-sectional surface area of the screen channel during maximum flow = 0.75 m2. The maximum free surface area in the clean screen = 0.5 m2. Use hL=1C⋅(V2−v2)(2⋅g) for calculating the head loss, the friction coefficient (C) for a clean screen is 0.7.
First, calculate the v in m/s.Answer= 0.56
Second, calculate the V in m/s. Answer=0.83
c) Calculate the head loss in m.Answer=0.027
1,500 m3/h. The dry weather flow (Qdwf) amounts 7,500 m3/day, with a BOD concentration of 300 mg/l.
a) Calculate the so-called peak flow factor. Answer=4.8
b) The cross-sectional surface area of the screen channel during maximum flow = 0.75 m2. The maximum free surface area in the clean screen = 0.5 m2. Use hL=1C⋅(V2−v2)(2⋅g) for calculating the head loss, the friction coefficient (C) for a clean screen is 0.7.
First, calculate the v in m/s.Answer= 0.56
Second, calculate the V in m/s. Answer=0.83
c) Calculate the head loss in m.Answer=0.027
Answered by
Ham
Bilal whay you passing wrong answer?? its not good man.
Answered by
Nilu
Ham thanks for Help,God Bless you.
Q-2C1,2C2,2D2
Q-2C1,2C2,2D2
Answered by
Mara *** Please, help me*
Thank you, Ham! You're a lifesaver!
Answered by
Nilu
Ham thanks for Help,God Bless you.
Q-2C1,2C2,2D2 answer please
Q-2C1,2C2,2D2 answer please
Answered by
Anonymous
3B and 3G anyone?? please help
Answered by
Anonymous
3B Chamber filter + Belt filter + Centrifuge
Answered by
Anonymous
3G??
Answered by
Kumar
The answers given by "Water Treatment - Ham, Sunday, November 24, 2013 at 10:24pm" is correct - Thanks Dear