Asked by Alan

Evaluate when x = 2, y = -5, z = 3.

x^2 - y = 3

3z - 4(y + 1) - y^2 = 0

x - yz = -13








Answered by Kuai
(2)^2-1(-5)
4+ 5 = 9

3(3) -4(-5+1)-(5)^2

9 + 16 -25 =0

2-(-5)(3)
2-(-15)
2+ 15 = 17