A hockey puck of mass 0.16 kg, sliding on a nearly frictionless surface of ice with a velocity of 2.0 m/s (E), strikes a second puck at rest with a mass of 0.17 kg. the first puck has a velocity of 1.5 (N 31 E) after the collision. Determine the velocity of the second puck after the collision.

Answer 1

please help Ms. SUE!!!!

Answer 2

a proton flying to the east near the surface of the earth at 1000mls. what is the magnitude of the force the proton feels due to earths magnetic field

Answer 3

X: m₁v₁=m₁u₁cosα+m₂u₂cosβ
Y: 0=m₁u₁sinα - m₂u₂cosβ
m₁v₁-m₁u₁cosα = m₂u₂cosβ …(1)
m₁u₁sinα= m₂u₂cosβ ………...(2)
Divide (2) by (1)
tanβ= m₁u₁sinα/ (m₁v₁-m₁u₁cosα) =
=sinα/ (1- cosα) =3.6
β=74.5º
u₂=m₁u₁sinα/ m₂cosβ= 0.16•2•sin31/0.17•sin 74.5 =1 m/s

Answer 4

to Anton:

F=qvB? where q=e
v: m mile/s -> m/s
B= 5•10⁻⁵ T

Answer 5

4.5