Question

A hockey puck with mass 0.160 kg is at rest at the origin (X = 0)a player applies a force of 0.250 N to the puck, parallel to the x- axis; he continues to apply this force until t = 2.00 s. a) What are the position and speed of the puck at t = 2.00 s? b)If the same force is again applied at t = 5.00 s, what are the position and speed of the puck at t = 7.00 s?

Answer 1

a = Fap/m = 0.25 / 0.160 = 1.56 m/s^2.

a. V = a*t = 1.56m/s^2 * 2s=3.125 m/s.
d = 0.5at^2 = 0.5*1.56*2^2 = 3.12 m.