Asked by Robin
Solve the separable differential equation 10x−6ysqrt(x^2+1)dy/dx=0. with the initial condition y(0)=4.
Answers
Answered by
Steve
10x−6y√(x^2+1)dy/dx=0
6y√(x^2+1) dy/dx = 10x
6y dy = 10x/√(x^2+1) dx
3y^2 = 10√(x^2+1) + c
Since y(0) = 4,
3*16 = 10+c
c = 38
now you have it.
6y√(x^2+1) dy/dx = 10x
6y dy = 10x/√(x^2+1) dx
3y^2 = 10√(x^2+1) + c
Since y(0) = 4,
3*16 = 10+c
c = 38
now you have it.
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