Asked by Robin
Solve the seperable differential equation 8yyΠ=x. Use the following initial condition: y(8)=4.
Express x^2 in terms of y.
Express x^2 in terms of y.
Answers
Answered by
Steve
8yy' = x
8y dy = x dx
4y^2 = 1/2 x^2 + c
4(16) = 1/2 (64) + c
c = 32
4y^2 = 1/2 x^2 + 32
8y^2 - x^2 = 64
y^2/8 - x^2/64 = 1
8y dy = x dx
4y^2 = 1/2 x^2 + c
4(16) = 1/2 (64) + c
c = 32
4y^2 = 1/2 x^2 + 32
8y^2 - x^2 = 64
y^2/8 - x^2/64 = 1
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