Asked by Laura
A 0.355-kg object undergoing SHM has ax = 2.30 m/s2 when x = 0.235 m. What is the time for one oscillation?
Answers
Answered by
Elena
x=Asinωt
v=Aωcosωt
a=-Aω²sinωt =- ω²x=-(2π/T)²x
|a/x| = (2π/T)²
T=2 π sqrt{ x/a}=2 π•sqrt(0.235/2.3)=2 s.
v=Aωcosωt
a=-Aω²sinωt =- ω²x=-(2π/T)²x
|a/x| = (2π/T)²
T=2 π sqrt{ x/a}=2 π•sqrt(0.235/2.3)=2 s.
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