Asked by Anonymous
a 60.0 g sample of chromium at 82.0 degrees celsius was place in 80.0 g of water. Assume there is no loss of heat to the environment. What is the final temperature of the water and chromium? The initial water temperature was 24.0 degrees celsius
Answers
Answered by
DrBob222
heat lost by Cr + heat gained by H2O = 0
[mass Cr x specific heat Cr x (Tfinal-Tinitial)] + [mass H2O x specific heat H2O x (Tfinal-Tinitial) = 0
Post your work if you get stuck.
[mass Cr x specific heat Cr x (Tfinal-Tinitial)] + [mass H2O x specific heat H2O x (Tfinal-Tinitial) = 0
Post your work if you get stuck.
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