Asked by Jane
A chemist has two solutions of sulfuric acid. The first is one half sulfuric acid and half water. The second is three-fourths sulfuric acid and one fourths water. He wishes to make 10 liters of a solution which is two-thirds sulfuric acid and one-thirds water. How many liters of each available solution should he use?
Please be as detailed as you can i really want to understand this problem more than getting the solution THANKS^^
Please be as detailed as you can i really want to understand this problem more than getting the solution THANKS^^
Answers
Answered by
Steve
add up the amounts of acid in each portion:
1/2 x + 3/4 (10-x) = 2/3 * 10
x = 10/3
so, 10/3 L of 50% acid
and 20/3 L of 75% acid
1/2 x + 3/4 (10-x) = 2/3 * 10
x = 10/3
so, 10/3 L of 50% acid
and 20/3 L of 75% acid
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