Asked by Ericka
I'm confused regarding the elimination method for
5x - 7y = -16,
2x + 8y = 26
5x - 7y = -16,
2x + 8y = 26
Answers
Answered by
Steve
#1: 5x - 7y = -16
#2: 2x + 8y = 26
To eliminate y, multiply #1 by 8 and #2 by 7 to get
40x - 56y = -128
14x + 56y = 182
If you add those two new equations, the y's are eliminated and you get
54x = 54
x=1
Now you can go back and calculate y from one of the original equations.
#2: 2x + 8y = 26
To eliminate y, multiply #1 by 8 and #2 by 7 to get
40x - 56y = -128
14x + 56y = 182
If you add those two new equations, the y's are eliminated and you get
54x = 54
x=1
Now you can go back and calculate y from one of the original equations.
Answered by
Bosnian
5 x - 7 y = - 16 Multiply both sides by - 2
- 10 x + 14 y = 32
2 x + 8 y = 26 Multiply both sides by 5
10 x + 40 y = 130
- 10 x + 14 y = 32
10 x + 40 y = 130 Add equations
- 10 x + 10 x + 14 y + 40 y = 32 + 130
54 y = 162 Divide both sides by 54
y = 162 / 54 = 3
5 x - 7 y = - 16
5 x - 7 * 3 = - 16
5 x - 21 = - 16 Add 21 to both sides
5 x - 21 + 21 = - 16 + 21
5 x = 5 Divide both sides by 5
x = 1
Solutions :
x = 1 , y = 3
- 10 x + 14 y = 32
2 x + 8 y = 26 Multiply both sides by 5
10 x + 40 y = 130
- 10 x + 14 y = 32
10 x + 40 y = 130 Add equations
- 10 x + 10 x + 14 y + 40 y = 32 + 130
54 y = 162 Divide both sides by 54
y = 162 / 54 = 3
5 x - 7 y = - 16
5 x - 7 * 3 = - 16
5 x - 21 = - 16 Add 21 to both sides
5 x - 21 + 21 = - 16 + 21
5 x = 5 Divide both sides by 5
x = 1
Solutions :
x = 1 , y = 3
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