Asked by DJ
very confused could someone help me with this
using the elimination method
5r-3s=16
3r+5s=30
using the elimination method
5r-3s=16
3r+5s=30
Answers
Answered by
yuuka
Let's say we want to eliminate 's'
So multiply 5 to the first equation
and multiply 3 to the second equation
we get:
25r - 15s = 80
9r + 15s = 90
use the elimination method by adding those two equation -15s and 15s cancels out
we get:
34r = 170
Then r = 5
So multiply 5 to the first equation
and multiply 3 to the second equation
we get:
25r - 15s = 80
9r + 15s = 90
use the elimination method by adding those two equation -15s and 15s cancels out
we get:
34r = 170
Then r = 5
Answered by
Anonymous
2c+3d+7-5c
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