Asked by Crystal
A soccer ball iskicked with an intial horizontal speed of 6 m/s and initial vertical speed of 3.5 m/s. Assume that the projection and landing height are the same, and neglect air resistance. Calculate the following
a) the ball's projection speed and angle
b)the ball's horizontal speed at .5 s into its flight
c) The ball's vertical speed at .5 s into its flight
d) the ball's height at its apex
e) the ball's flight time
f)the ball's flight distance
a) the ball's projection speed and angle
b)the ball's horizontal speed at .5 s into its flight
c) The ball's vertical speed at .5 s into its flight
d) the ball's height at its apex
e) the ball's flight time
f)the ball's flight distance
Answers
Answered by
Henry
Xo = 6 m/s.
Yo = 3.5 m/s.
a. tanA = Yo/Xo = 3.5/6 = 0.58333
A = 30.3o
Vo=Xo/cosA = 6/cos30.3 = 6.95m/s[30.3o]
b. X = Xo = 6 m/s. It does not change.
c. Y = Yo + g*t
Y = 3.5 - 9.8*0.5 = -1.4 m/s. The negative sign means the ball is falling.
d. h=(Y^2-Yo^2)/2g=(0-3.5^2)/-19.6 = 0.625 m.
e. Y = Yo + g*t = 0 @ max. ht.
Tr = (V-Vo)/g = (0-3.5)/-9.8=0.357 s =
Rise time.
Tf = Tr = 0.357 s. = Fall time.
T = Tr + Tf = 0.357 + 0.367 = 0.714 s.
f. D = Xo * t = 6m/s * 0.714s = 4.29 m.
= 0.357 = 0.714 s.
Yo = 3.5 m/s.
a. tanA = Yo/Xo = 3.5/6 = 0.58333
A = 30.3o
Vo=Xo/cosA = 6/cos30.3 = 6.95m/s[30.3o]
b. X = Xo = 6 m/s. It does not change.
c. Y = Yo + g*t
Y = 3.5 - 9.8*0.5 = -1.4 m/s. The negative sign means the ball is falling.
d. h=(Y^2-Yo^2)/2g=(0-3.5^2)/-19.6 = 0.625 m.
e. Y = Yo + g*t = 0 @ max. ht.
Tr = (V-Vo)/g = (0-3.5)/-9.8=0.357 s =
Rise time.
Tf = Tr = 0.357 s. = Fall time.
T = Tr + Tf = 0.357 + 0.367 = 0.714 s.
f. D = Xo * t = 6m/s * 0.714s = 4.29 m.
= 0.357 = 0.714 s.
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