Asked by lisa
The height of a soccer ball that is kicked from the ground can
be approximated by the function:
y = -12⋅x2 + 48⋅x
where y is the height of the soccer ball in feet x seconds after it is kicked.
Find the time it takes the soccer ball to reach its maximum height: _____ seconds
What is the soccer ball’s maximum height:___ feet
Find the time it takes from the moment the soccer ball is kicked until it returns to the ground: ____ seconds
be approximated by the function:
y = -12⋅x2 + 48⋅x
where y is the height of the soccer ball in feet x seconds after it is kicked.
Find the time it takes the soccer ball to reach its maximum height: _____ seconds
What is the soccer ball’s maximum height:___ feet
Find the time it takes from the moment the soccer ball is kicked until it returns to the ground: ____ seconds
Answers
Answered by
Henry
Since the parabola opens downward, the vertex is the max. point on the curve.
Y = -12x^2 + 48x
1. h = Xv = -B/2A = -48/-24 = 2 Seconds.
2. k = Yv = -12*2^2 + 48*2 = 48 Ft.
V(x,y)= (2,48).
3. Tr = Tf = 2 s.
T = 2 + 2 = 4 s.
Tr = Rise time.
Tf = Fall time.
Y = -12x^2 + 48x
1. h = Xv = -B/2A = -48/-24 = 2 Seconds.
2. k = Yv = -12*2^2 + 48*2 = 48 Ft.
V(x,y)= (2,48).
3. Tr = Tf = 2 s.
T = 2 + 2 = 4 s.
Tr = Rise time.
Tf = Fall time.
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