Question

Under certain conditions, the reaction
3A + 2B -> 4C
was observed to proceed at a rate of
0.00348 M· s−1. What was the corresponding
rate of change in reactant A?

Answer 1

rate = -(1/3)(change in A)/time.
0.00348 = -(1/3)dA/dt.
Solve for dA/dT