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Under certain conditions, the reaction

3A + 2B -> 4C
was observed to proceed at a rate of
0.00348 M· s−1. What was the corresponding
rate of change in reactant A?

1 answer

rate = -(1/3)(change in A)/time.
0.00348 = -(1/3)dA/dt.
Solve for dA/dT
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