Asked by Anonymous
Calculate the number of moles in 50 kg of ammonium sulfate (NH4)2 SO4 (with the steps please)
Answers
Answered by
DrBob222
mols = grams/molar mass
Answered by
anonymous _25
ammonium sulfate {nh4}2so4
50 kg =50000g
mass of [ nh4]2so4
=132
n=378.7878
50 kg =50000g
mass of [ nh4]2so4
=132
n=378.7878
Answered by
Bot
To calculate the number of moles in 50 kg of ammonium sulfate, we need to follow these steps:
1. Convert the mass of ammonium sulfate from kg to g:
50 kg x 1000 g/kg = 50,000 g
2. Find the molar mass of ammonium sulfate by adding up the atomic masses of all the elements in the compound:
Molar mass of (NH4)2SO4 = 2(N) + 8(H) + S + 4(O)
= 2(14.01 g/mol) + 8(1.01 g/mol) + 32.06 g/mol + 4(16.00 g/mol)
= 132.14 g/mol
3. Calculate the number of moles of ammonium sulfate using the formula:
moles = grams / molar mass
moles = 50,000 g / 132.14 g/mol
moles = 378.79 mol
Therefore, there are 378.79 moles of ammonium sulfate in 50 kg of (NH4)2SO4.
1. Convert the mass of ammonium sulfate from kg to g:
50 kg x 1000 g/kg = 50,000 g
2. Find the molar mass of ammonium sulfate by adding up the atomic masses of all the elements in the compound:
Molar mass of (NH4)2SO4 = 2(N) + 8(H) + S + 4(O)
= 2(14.01 g/mol) + 8(1.01 g/mol) + 32.06 g/mol + 4(16.00 g/mol)
= 132.14 g/mol
3. Calculate the number of moles of ammonium sulfate using the formula:
moles = grams / molar mass
moles = 50,000 g / 132.14 g/mol
moles = 378.79 mol
Therefore, there are 378.79 moles of ammonium sulfate in 50 kg of (NH4)2SO4.
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