Asked by Nada
Calculate the number of moles of sulfur in 57.1 g of sulfur. Note that molar mass of sulfur is 32.06 g/mol
Answers
Answered by
oobleck
57.1g * 1mole/32.06g = 57.1/32.06 moles
Answered by
DrBob222
Not to be nit picky (I REALLY don't want to be nit picky) but some would argue that sulfur is S8 and the molar mass is 32.06*8 or 256.48. Frankly, although I agree sulfur actually is S8, I think that just complicates stoichiometry problems because it makes equations 8 times larger than they would otherwise be AND it doesn't change the end product. For example, burning sulfur in oxygen. Instead of the equation being
S + O2 ==> SO2 and 32.06 g S forming 64.06 g SO2 you get
S8 + 16O2 ==> 8SO2
32.06/256.48 = 0.125 mols S
0.125 moles S x (8 moles SO2/1 mol S8) = 1 mol SO2.
1 mol SO2 x 64.06 g/mol = 64.06 g SO2 formed. Same answer but MUCH more work to get there. This is just a nice way of reminding students that H2, N2, O2, F2, Cl2, Br2 and I2 are diatomic gaseous element while S exists as S8 and P exists as P4.
There is a mnemonic for that.
H-N-O-F-Cl-Br-I
Have No Fear Of Ice Cold Beer and their twins S8 and P4
Just a little extra information for those interested.
S + O2 ==> SO2 and 32.06 g S forming 64.06 g SO2 you get
S8 + 16O2 ==> 8SO2
32.06/256.48 = 0.125 mols S
0.125 moles S x (8 moles SO2/1 mol S8) = 1 mol SO2.
1 mol SO2 x 64.06 g/mol = 64.06 g SO2 formed. Same answer but MUCH more work to get there. This is just a nice way of reminding students that H2, N2, O2, F2, Cl2, Br2 and I2 are diatomic gaseous element while S exists as S8 and P exists as P4.
There is a mnemonic for that.
H-N-O-F-Cl-Br-I
Have No Fear Of Ice Cold Beer and their twins S8 and P4
Just a little extra information for those interested.
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