Question

A ball is released from a hot air balloon moving downward with a velocity of
-10.0 meters/second and a height of 1,000 meters. How long did it take the ball to reach the surface of Earth? Given: g = -9.8 meters/second2.

Answer 1

h= v₀t + gt²/2
gt²+2v₀t-2•h = 0
9.8t²+2•10t- 2000=0
t=[20±sqrt{400+4•9.8•1000}]/2•9.8 =
=(20±199)/19.6 =>
t=11.2 s.

Answer 2

lol

Answer 3

its 11.2s