Asked by Marissa
I'm struggling some with the us of trigonomic properties.
The problem is integral sin(2x)sec(x) dx and I don't understand how sin(2x)sec(x) simplifies into 2sin(x).
The problem is integral sin(2x)sec(x) dx and I don't understand how sin(2x)sec(x) simplifies into 2sin(x).
Answers
Answered by
Reiny
sin(2x)sec(x)
= 2sinx cosx/cosx , basic identity look in your notes
= 2sinx
so ∫sin(2x)secx dx
= ∫ 2sinx dx
= -2cosx + c
= 2sinx cosx/cosx , basic identity look in your notes
= 2sinx
so ∫sin(2x)secx dx
= ∫ 2sinx dx
= -2cosx + c
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