Asked by Dee
Use a calculator to help solve the problem.
One isotope of holmium, 162Ho, has a half life of 22 minutes. The half-life of a second isotope, 164Ho, is 37 minutes. Starting with a sample containing equal amounts, find the ratio of the amounts of 162Ho to 164Ho after two hours. (Round your answer to three decimal places.)
One isotope of holmium, 162Ho, has a half life of 22 minutes. The half-life of a second isotope, 164Ho, is 37 minutes. Starting with a sample containing equal amounts, find the ratio of the amounts of 162Ho to 164Ho after two hours. (Round your answer to three decimal places.)
Answers
Answered by
Reiny
Assume we start with 1 unit of each
after t = 2 hrs = 120 minutes
amount of 162ho = 1(1/2)^(120/22)
amount of 164ho = 1(1/2)^(120/37)
ratio of the two = 1(1/2)^(120/22) / 1(1/2)^(120/37)
= (1/2)^(120/22 - 120/37)
= (1/2)^(900/407)
= .2159
= .216 to 3 decimals
= 216 : 1000
=27 : 125
after t = 2 hrs = 120 minutes
amount of 162ho = 1(1/2)^(120/22)
amount of 164ho = 1(1/2)^(120/37)
ratio of the two = 1(1/2)^(120/22) / 1(1/2)^(120/37)
= (1/2)^(120/22 - 120/37)
= (1/2)^(900/407)
= .2159
= .216 to 3 decimals
= 216 : 1000
=27 : 125
Answered by
bobpursley
amount162/amount164= 100/100 * e^(-.692*60/22)/e^(-.692*60/37)
e^-.692*60(1/22-1/37)=.465
check my work.
e^-.692*60(1/22-1/37)=.465
check my work.
Answered by
Dee
thank you Reiny and Bob
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