A ground state hydrogen atom absorbs a photon of light having a wavelength of 94.96 nm. It then gives off a photon having a wavelength of 95 nm. What is the final state of the hydrogen atom?

Answer 1

You have two problems in one here. The first one is to start with the electron in its ground state and determine to which level (shell) the photon takes it. The second part starts with the electron in that as a starting position gives the wavelength and asks for the final shell.
#1.
delta E = hc/wavelength
Substitute h, c & wavelength and calculate delta E. Then use
delta E = 2.180E18 J x (1/1 - 1/n^2)
The 1/1 is 1/n^2 for the electron in n = 1. The n^2 is the shell to which the electron is being promoted. Substitute and solve for n.

Second part.
delta E = hc/wavelength. Substitute and solve for delta E.
delta E = 2.180E18J x (1/x^2 - 1/n^2)
The n^2 is the shell to which the electron has been promoted from the previous part and the x = the final destination of the electron. Substitute and solve for x, then

Answer 2

ok, i think i got 5 for an answer
do you think this is correct??