Asked by Amy

The weights of the fish in a certain lake are normally distributed with a mean of 15lbs. and standard deviation of 6lbs. If a sample of 5 fish are taken from the lake, find the probability their means weights are between 12.6 lbs. and 18.6 lbs.
Answered by Kuai
z = (x -x bar)/ std dev/sqrt(n)
z = (12.6-15)/ 6/sqrt(5)
z = -0.89
.1867

z = (x -x bar)/ (std dev/sqrt(n))
z = (18.6-15)/ 6/sqrt(5)
z= 1.34
.9099

.9909-.1867 = .8042
Answered by Anonymous
what is the sqrt?
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