Asked by Eve
Find the integral:8x^7+6/(x^8+6x)^2
I got ln(x^8+6x)^2 but apparently that is wrong.
I got ln(x^8+6x)^2 but apparently that is wrong.
Answers
Answered by
Steve
it surely is wrong
If u = x^8 + 6x, then you have
du/u^2
integral is -1/u
try taking the derivative of ln(u^2) and see what you get. Don't forget the chain rule.
If u = x^8 + 6x, then you have
du/u^2
integral is -1/u
try taking the derivative of ln(u^2) and see what you get. Don't forget the chain rule.
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