Asked by Aladdyn
Find the integral of (sin x)^4 times cos x with limits 0 to pie/2
Answers
Answered by
huy
∫(sinx)^4*cosxdx
set u= sinx=> du= cosxdx
the function looks like this :
∫u^4du = u^5/5 and what you need is to put limits
set u= sinx=> du= cosxdx
the function looks like this :
∫u^4du = u^5/5 and what you need is to put limits
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