Asked by Michelle
Having some difficulty with this question. Can anyone help me please? Thank you in advance for your time.
85 microliters of acetophenone (120.15 g/mol, 1.03 g/ml) was reacted with 3.0mL of aq NaOCl (5% available chlorine) to give 72mg of benzoic acid (122.12 g/mol) as a white solid. What is the percent yield of the product? Watch out for significant figures.
85 microliters of acetophenone (120.15 g/mol, 1.03 g/ml) was reacted with 3.0mL of aq NaOCl (5% available chlorine) to give 72mg of benzoic acid (122.12 g/mol) as a white solid. What is the percent yield of the product? Watch out for significant figures.
Answers
Answered by
DrBob222
1 mol acetophenone ==> 1 mol benzoic acid
85 uL = 85E-3 mL
mass acetophenone = 85E-3 mL x 1.03 g/mL = ?g acetophenone
mols acetophenone = grams/molar mass
mols benzoic acid = mols acetophenone
g benzoic acid = mols x molar mass and this is the theoretical yield in grams.
(0.072/theoretical yield)*100 = ? and round to 2 s.f. Looks like about 81%
85 uL = 85E-3 mL
mass acetophenone = 85E-3 mL x 1.03 g/mL = ?g acetophenone
mols acetophenone = grams/molar mass
mols benzoic acid = mols acetophenone
g benzoic acid = mols x molar mass and this is the theoretical yield in grams.
(0.072/theoretical yield)*100 = ? and round to 2 s.f. Looks like about 81%
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