Asked by Anonymous


Wouldn't it be 3*0.234 instead of 2* 0.234? since....2Al3+ +3SO4 2- ----> Al2(SO4)3

4.) A solution is prepared by dissolving 25.0 g of aluminum sulfate in enough water to make 125.0 mL of stock solution. A 10.0 mL aliquot (portion) of this stock solution is then removed and added to 15.0 mL of water. Calculate the concentrations of all ions in the final solution.

My answer:

[Al2(SO4)3]= 0.234M

[Al3+]= 0.468M

[SO4 2-]= 0.702M

I would have use 0.2338 x 2 = 0.0701 for SO4^2-. The others look ok.

Answers

Answered by DrBob222
Of course, that's the only way to get 0.701. You should check all of these closely, especially for typos. My eyesight is not all that good. I did proof each answer before posting but sometimes I miss them the second time through.
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