Question

A pump lifts 200kg of water per hour a height of 6.0m .

Part A
What is the minimum necessary power output rating of the water pump in watts?

Part B
What is the minimum necessary power output rating of the water pump in horsepower?

Answer 1

F = m*g = 200kg * 9.8N/kg = 19,600 N.

P = F * h/t = 19600 * 6/3600s.=32.67 J/s
= 32.67 Watts.

(32.67/746) * 1hp = 0.0438 hp.

Answer 2

P=w/t
=F*x/t
=m*a*x/t
=200kg*9.8m/s^2*6m/3600s
≈3.267W

=(3.267W/1)*(1hp/746W)
≈0.00438hp