Identify the following chemical equations by type.

Question

1. If an electric discharge produces 500 cm3 of ozone (O3), how many cm3 of oxygen (O2) are required?

3O2(g) ---> 2O3(g)




2. When 2.75 dm3 of O2 react with an excess of glucose (C6H12O2), according to the reaction below, what volume of carbon dioxide will be produced?

6O2(g) + C6H12O6(s) ---> 6H2O(g) + 6CO2(g)



3. If an excess of nitrogen gas reacts with 25.0 L of hydrogen gas, according to the reaction below, how many L of ammonia will be produced?

N2(g) + 3H2(g) ---> 2NH3(g)


4. How many cm3 of oxygen would be required to react comp

Answer 1

1. If an electric discharge produces 500 cm3 of ozone (O3), how many cm3 of oxygen (O2) are required?

3O2(g) ---> 2O3(g)

This is a synthesis. Since these are gases we can use cc as if they were mols.
500 cc O3 x (3 mols O2/2 mols O3) = 5-- x 3/2 = ?

Answer 2

#2 and #3 are worked the same way as #1.
#2 is combustion.
#3 is synthesis
#4 doesn't make sense to me.

Answer 3

Answers;

1.
(500 cm^3 O3)*(3 moles O2/2 moles O3) = 500*(3/2) cm^3 O2 = 750 cm^3 O2

2)
(2.75 dm3 O2) x (6 dm3 CO2 / 6 dm3 O2) = 2.75 dm3 CO2

3)
(25.0 L H2) x (2 L NH3 / 3 L H2) = 16.7 L NH3

4)
(250.0 cm3 H2) x (2 cm3 H2 / 1 cm3 O2) = 500.0 cm3 O2