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Identify the following chemical equations by type.
1. If an electric discharge produces 500 cm3 of ozone (O3), how many cm3 of
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Answers; 1. (500 cm^3 O3)*(3 moles O2/2 moles O3) = 500*(3/2) cm^3 O2 = 750 cm^3 O2 2) (2.75 dm3 O2) x (6 dm3 CO2 / 6 dm3 O2) = 2.75 dm3 CO2 3) (25.0 L H2) x (2 L NH3 / 3 L H2) = 16.7 L NH3 4) (250.0 cm3 H2) x (2 cm3 H2 / 1 cm3 O2) = 500.0 cm3 O2
