If f(x) = 2sin(5x)arcsin(x), find f'(x).

COS[ARCSIN (SIN 3PI/4)] =COS[ARCSIN (SQRT2/2)] =COS [PI/4] = SQRT2/2

Find arcsin [cos (Pi/2)] The answer is 0. How do you solve this problem? Thanks.

What is the arcsin of (pi/2)?

sin(2arccos(1/4) - arcsin (-1/2))

Consider the function y=arcsin x. a) Use a grapging utility to complete the table. x = -1 -...

Evaluate cos (2 arcsin (1/4))

how do I solve this arcsin(4/5) note that I am not looking for about 53 degrees I believe...

I am given arcsin (sin 4pi) do the arc sin and sin cancel out? How do we solve this?

cos(arcsin(7/8)) =

cos(arcsin(−5/6))

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