Asked by Kate
how do I solve this
arcsin(4/5)
note that I am not looking for about 53 degrees
I believe I'm suppose to solve euler's formula for x
i.e.
sin (x) = (e^(ix) - e^(-ix))/(2i)
where x is in radians
hence I would do something like this
sin (x) = (e^(ix) - e^(-ix))/(2i) = 4/5
(e^(ix) - e^(-ix))/(2i) = 4/5
solve the equation above for x
this is were I need help if somebody could just show me quickly how to do this that would be great!!!
If I remeber correctly I need to use cis(x) or something right?
arcsin(4/5)
note that I am not looking for about 53 degrees
I believe I'm suppose to solve euler's formula for x
i.e.
sin (x) = (e^(ix) - e^(-ix))/(2i)
where x is in radians
hence I would do something like this
sin (x) = (e^(ix) - e^(-ix))/(2i) = 4/5
(e^(ix) - e^(-ix))/(2i) = 4/5
solve the equation above for x
this is were I need help if somebody could just show me quickly how to do this that would be great!!!
If I remeber correctly I need to use cis(x) or something right?
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