Asked by Anonymous

If 2.0 Grams of anhydrous sodium sulfate are mixed with 2.0 grams of calcium chloride dihydrate and 2.0 grams of calcium sulfate dihydrate are collected, what is the percent yield? DO NOT ROUND A NUMBER IF USED IN A SUBSEQUENT CALCULATION
Answered by Tanner
First you need to find the limited reactant. You do this by dividing the 2.0 g of NaSO4 by it's molar mass as well as the 2.0 g of Calcium Sulfate dihyrdate (CaCl2 + 2H20) You'll find that the Calcium sulfate is the limited reactant. From there you Take the moles of Calcium chloride dihydrate(which you just found because you found it to be the limited reactant) and times it by the molar mass of Calcium Sulfate dihydrate. From there you get the theoretical yield. Now you just divide the actual by the theoretical. so 2.0/2.342 (grams) to get approximately 85%
Answered by who cares
Hey tanner, you did your math wrong and you confused a bunch of words in your paragraph. Double check a post before you submit it buddy.
Answered by Lol
I actually found tanners math to be great. Some of the words were off though.
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