Asked by Kaylee
Anhydrous CuSO4 can be used to dry liquids in which it is insoluble. The CuSO4 is converted to CuSO4.5H2O, which can be filtered off from the liquid.
What is the minimum mass of anhydrous CuSO4 needed to remove 12.4g H2O from a tankful of gasoline?
What is the minimum mass of anhydrous CuSO4 needed to remove 12.4g H2O from a tankful of gasoline?
Answers
Answered by
bobpursley
how many moles of H2O are in 12.4g?
moles H2O = 12.4/18 grams
so to get CuSO4.5H2O, you need (12.4/18)*1/5 moles of CuSO4
figure how many grams that is.
moles H2O = 12.4/18 grams
so to get CuSO4.5H2O, you need (12.4/18)*1/5 moles of CuSO4
figure how many grams that is.