Question
A stone is thrown in a vertically upward direction with a velocity of 5 m s -1 . If the acceleration of the stone during its motion is 10 m s-2 in the downward direction, what will be the height attained by the stone and how much time will it take to reach there?
Answers
Henry
V^2 = Vo^2 + 2g*h
h = (V^2-Vo^2)/2g
h = (0-5^2)/-20 = 1.25 m.
V = Vo + g*t
t = (V-Vo)/g = (0-5)/-10 = 0.5 s.
h = (V^2-Vo^2)/2g
h = (0-5^2)/-20 = 1.25 m.
V = Vo + g*t
t = (V-Vo)/g = (0-5)/-10 = 0.5 s.