mols NaOH = grams/molar mass
M NaOH = mols/L solution. L soln = 0.1 L in the problem.
Then (OH^-) = (NaOH)
pOH = -log(OH^-)
pH + pOH = pKw = 14. You know pOH and pKw, solve for pH.
Post your work if you get stuck.
A solution of NaOH(aq) contains 5.2 g of NaOH(s) per 100.0 mL of solution. Calculate the pH and the pOH of the solution at 25 °C.
2 answers
2314