What mass of Na2CrO4 is required to precipitate all of the silver ions from 71.0 mL of a 0.101 M solution of AgNO3?

Answer 1

AgNO3 + Na2CrO4 ==> Ag2CrO4 + 2NaNO3

mols AgNO3 = M x L = ?
Using the coefficients in the balanced equation, convert mols AgNO3 to mols Na2CrO4.
Now convert mols Na2CrO4 to gram. g = mols x molar mass