Asked by Brittany
A solution contains an unknown mass of dissolved silver ions. When potassium chloride is added to the solution, a white precipitate forms. The precipitate is filtered and dried and then found to have a mass of 245 mg. What mass of silver was in the original solution? (Assume that all of the silver was precipitated out of solution by the reaction.)
Answers
Answered by
DrBob222
245 mg = 0.245 grams.
moles AgCl = grams/molar mass AgCl.
Mols Ag must be the same as moles AgCl. Convert moles Ag to grams Ag. g = moles x molar mass.
moles AgCl = grams/molar mass AgCl.
Mols Ag must be the same as moles AgCl. Convert moles Ag to grams Ag. g = moles x molar mass.
Answered by
Nicholas Craddieth
0.245
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