Question
A solution contains an unknown amount of dissolved magnesium. Addition of 3.38×10−2mol of Na2CO3 causes complete precipitation of all of the magnesium.
What mass of magnesium was dissolved in this solution?
What mass of magnesium was dissolved in this solution?
Answers
DrBob222
Mg ^2+(aq) + Na2CO3(aq) ==> MgCO3(s) + 2Na^2+
mols Na2CO3 = 0.0338
mols Mg = mols Na2CO3 (look at the coefficients in the balanced equation.
g Mg = mols Mg x atomic mass Mg = ?
mols Na2CO3 = 0.0338
mols Mg = mols Na2CO3 (look at the coefficients in the balanced equation.
g Mg = mols Mg x atomic mass Mg = ?
Anonymous
2.5