Asked by steve
how to find derivate of:
y=(-4x^2+8)/(x^2+2)^2
y=(-4x^2+8)/(x^2+2)^2
Answers
Answered by
Reiny
Use the quotient rule, I will give you the first line
dy/dx = [-8x(x^2+2)^2 - (-4x^2+8)(2)x^2+2)(2x)]/(x^2+2)^4
dy/dx = [-8x(x^2+2)^2 - (-4x^2+8)(2)x^2+2)(2x)]/(x^2+2)^4
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