Ask a New Question
Search
Asked by
maggie
Find the derivate of the function
f(x) = 2x2 + 23x + 5
What is the value of this derivative when x = 19
Answers
Answers
Answered by
Henry
F(X) = 2X^2 + 23X + 5.
F'(x) = 4X + 23,
F'(19) = 4*19 + 23 = 99.
Related Questions
Related
how to find derivate of: y=(-4x^2+8)/(x^2+2)^2
find the derivate of the function Y=(2x+3)^4(3x+1)^-2?
find third derivate f(x)=x/x+1
hello i need help for derivate this function: x+1+1/(x+2) thanks for your help
use the first derivate test to locate the maxima and minima of y = x^(1/3)
use the second derivate test to locate the maxima and minima of y = x^2 + 2x - 3
what derivate rule this two function is using y=5+e^4t+5^2 y=-2x^-1 -1/x^3 +3x^-4
what derivate rule this two function is using y=5+e^4t+5^2 y=-2x^-1 -1/x^3 +3x^-4 example quoti...
what derivate rule this two function is using y=5+e^4t+5^2 y=-2x^-1 -1/x^3 +3x^-4 example quoti...
find a derivate of 3x^2+7