Asked by hannah
The cost of producing d hundred plastic toy dinosaurs per day in a small company
is C(d) = 120 + 30d + 1
8d4 dollars. This company is currently producing 500 di-
nosaurs each day. Using calculus, estimate how much the company should change the
production to make their daily cost approximately 250 dollars.
do i take the derivative of C(d)? i am so confused
is C(d) = 120 + 30d + 1
8d4 dollars. This company is currently producing 500 di-
nosaurs each day. Using calculus, estimate how much the company should change the
production to make their daily cost approximately 250 dollars.
do i take the derivative of C(d)? i am so confused
Answers
Answered by
Reiny
using Calculus ?????
150 = 120 + 30d + 1
since we are estimation
30 = appr 30d
d = 1 ??????
This question makes no sense to me the way you typed it
what is 8d4 dollars ??
150 = 120 + 30d + 1
since we are estimation
30 = appr 30d
d = 1 ??????
This question makes no sense to me the way you typed it
what is 8d4 dollars ??
Answered by
hannah
C(d) = 120 + 30d + 1/8 d^4 sorry the formating gets off
Answered by
Steve
I'm also confused on where the calculus comes in. Currently,
C(5) = 348.125
We want
120 + 30d + 1/8 d^4 = 250
d=3.62
So, making 362 dinos will cost $250
Solving quartics is not easy, but maybe you're supposed to bring in calculus via the Newton-Raphson method.
Also, this factory is strange, having a production cost that rises as d^4!
C(5) = 348.125
We want
120 + 30d + 1/8 d^4 = 250
d=3.62
So, making 362 dinos will cost $250
Solving quartics is not easy, but maybe you're supposed to bring in calculus via the Newton-Raphson method.
Also, this factory is strange, having a production cost that rises as d^4!
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