Asked by Anonymous
A football is thrown upward at a 30 degree angle to the horizontal. To throw a 40.0-m pass, what must be the initial speed of the ball?
Answers
Answered by
Henry
Range = Vo^2*sin(2A)/g
Range = Vo^2*sin(60)/9.8 = 40
0.08837Vo^2 = 40
Vo^2 = 452.6
Vo = 21.3 m/s
Range = Vo^2*sin(60)/9.8 = 40
0.08837Vo^2 = 40
Vo^2 = 452.6
Vo = 21.3 m/s
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