let the quarterly rate be i
then 3800(1+i)^8 = 4300
(1+i)^8 = 1.1315789....
take (1/8)th root , (exponent of 1/8)
1+i = 1.01557..
i = .01557...
annual rate is 4i = .06229
the rate is 6.229% per annum, compounded quarterly.
If $3800 is invested in a savings account for which interest is compounded quarterly, and if the $3800 turns into $4300 in 2 years, what is the interest rate of the savings account?
4 answers
4300=3800(1+i/4)^4t where t is 2, solve for i.
43/38= (1+i/4)^8
take the log of each side
log43-log38=8(1+i/4)
solve for i.
43/38= (1+i/4)^8
take the log of each side
log43-log38=8(1+i/4)
solve for i.
I don't get it
107.80